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Coherent Monochromatic light of wavelength H in air is incident on two narrow slits, the centers of which are 2 mm apart. The interference pattern is observed on a screen 5.0 m away is represented on a graph of light intensity I as a function of position x on the screen.

a) At point P in the diagram, there is a minimum in the interference pattern. Determine the path difference between the light arriving at this point from the two slits. (P is 1.5 wavelengths from 0)

b) Determine the wavelength of light.
ah, good ole physics...learning it right now, but my eyes are hurtingSad I'm sure some college student can help youToungue

all I can think of right now is there's a formula that should work if you plug stuff inXD
That's what I think too XD

but I only have a formula that lets you solve part a if you know the answer to b, and vice versa Closedeyes

yoshidude65 Wrote:
That's what I think too XD

but I only have a formula that lets you solve part a if you know the answer to b, and vice versa Closedeyes


what's this formula? I think the trick is knowing something about minimum interference is at ?n+1/2?, where n is an integer lambda...but I'd have to review my optics...I'm pretty bad at physics.

Great, I get the person who's bad at physics Closedeyes j/k Toungue

I've got:

dsin(theta) = m*lambda (constructive Interference)
dsin(theta) = (m+1/2)*lambda (destructive Interference)

y = (m*lamda*L)/d

y is distance to the mth fringe
L is distance from the slits to the screen
d is the distance between 2 slits
My math professor would say: First think what you have, then see what they ask for and finally fill the gaps. Of course this was about "demostrations" (i don't know if you call them this way) but is also a nice way to solve some problems... and you already have some formulas.

Sorry mate i can't remember physics it's been a while.
What's path difference? I can't remember doing anything related to it last year. I looked it up just now, but what I found doesn't come close to any of the equations you have, so I'm not sure it's right...
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